Realated Questions
In the adjoining figure, AC + AB = 5 AD and AC - AD = 8. The area of the rectangle ABCD is:
The sides of a triangle are 5, 12 and 13 units respectively. A rectangle is constructed which is equal in area to the triangle and has a width of 10 units. Then the perimeter of the rectangle is
ABCD is a square of area 4, which is divided into four non -overlapping triangles as shown in the figure. The sum of the perimeters of the triangles is: