Consider the sequence of numbers a1, a2, a3, ..... to infinity where a1 = 81.33 and a2 = –19 and aj = aj–1 –aj–2 for j ≥ 3. What is the sum of the first 6002 terms of this sequence

–100.33

–30.00

62.33

119.33

Correct Answer : C

An old man has Rs. (1! + 2! + 3! + ...+ 50!), all of which he wants to divide equally (without fractions) among his n children. Then, n may be

If the sum to infinity of the series 2+(2 – d)2/3+(2+d)4/9+(2+3d)8/27+…..∞ is 5/2,what is the value of d

(51 + 52 + 53 + ……… + 100) is equal to: